The given expression: 0 = x^2+6x+9 is an equation, not a function. We can express the related function as: f (x) = x^2+6x+9 = (x+3)^2 In which case the given equation represents the zeros …

Mar 12, 2017 · √6x − 5+10 −10 = 3 −10 ⇒ √6x −5 = −7 square both sides (√6x − 5)2 = (− 7)2 ⇒ 6x − 5 = 49 add 5 to both sides. 6x−5 +5 = 49+ 5 ⇒ 6x = 54 divide both sides by 6 6x 6 = 54 6 ⇒ …

Simplify the expression (4x+8)+ (-6x). Explain how the associative and commutative properties were used to solve the expression? Algebra

Jan 29, 2017 · 6x^2+x-1 = (2x+1) (3x-1) Here are a couple of methods (in no particular order): Method 1 Note that: (ax+1) (bx-1) = abx^2+ (b-a)x-1 Comparing with: 6x^2+x-1 we want to find …

How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs

Using [1] 3y+6x=-24 3y=-24-6x color (blue) (y=-8-2xcolor (white) (888) [3] Substituting [3] in [2] z=-2 (-8-2x)-16 z=16+4x-16 z=4x Now find y in terms of x. This is equation [3] we found earlier.

Explanation: The problem #int (2x)/ (x^2+6x+13)dx# can be solved By the method as shown below. Let #u=x^2+6x+13#, #du= (2x+6)dx# Further, in the numerator, we have only …

Measure of angle LhatOM = 48^0 7x-92+6x+12=180 1) Combine like terms 7x - 92 + 6x + 12 =180 13x - 80= 180 2) Add color (blue) (80) to both sides (13x) - cancel80 color (blue) (+ …

0, 1, 3 To solve this, we set the equation equal to 0 and factor it. First, we can factor out 6x to get 6x(x^2-4x+3)=0. Next we can factor out the area in parentheses. To do this, we need to find …

(x+6)/ (x-6) >"factorise numerator/denominator" • x^2+12x+36 "'split '12x into 6x + 6x" rArrx^2+6x+6x+36 "factor each 'pair' by taking out a "color (blue)"common ...