What do the symbols d/dx and dy/dx mean? - Mathematics Stack …
May 2, 2015 · Okay this may sound stupid but I need a little help... What do $\Large \frac {d} {dx}$ and $\Large \frac {dy} {dx}$ mean? I need a thorough explanation. Thanks.
What is the difference between $dy$ and $Δy$ and why is $dx$ is …
Jul 31, 2020 · For examples, this $\mathrm {d}y$ as $\delta y$ and $\mathrm {d}x$ as $\delta x$ notation is used in videos like the ones mentioned in a comment by the OP Yashasv Prajapati: …
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In differential calculus, why is dy/dx written as d/dx ( y)?
In differential calculus, We know that dy/dx is the ratio between the change in y and the change in x. In other words, the rate of change in y with respect to x. Then, why is dy/dx written as d/dx...
Where does the $dy$ go in the process of integration?
Jul 25, 2019 · Yes, ∫dy is somehow the same as y! imagine dy as a bit of y and ∫ as a sum over the bits.
Meaning of dx, dy, du (u-substitution) - Mathematics Stack Exchange
Apr 8, 2018 · Meaning of dx, dy, du (u-substitution) Ask Question Asked 7 years, 7 months ago Modified 6 years, 6 months ago
calculus - What is $dy/dy$? - Mathematics Stack Exchange
Sorry for reviving this, but how does this work if y is a constant, for example, y = 10. dy/dy = d (10)/dy. So 1= 0? that doesn't make sense
Why is $dy dx = r dr d \\theta$ - Mathematics Stack Exchange
Possible Duplicate: Explain $\iint \mathrm dx\mathrm dy = \iint r \mathrm d\alpha\mathrm dr$ I'm reading the proof of Gaussian integration. When we change to polar coordinates, why do we …
calculus - Why is the 2nd derivative written as $\frac {\mathrm …
Mar 5, 2011 · In Leibniz notation, the 2nd derivative is written as $$\dfrac {\mathrm d^2y} {\mathrm dx^2}\ ?$$ Why is the location of the $2$ in different places in the $\mathrm …
Integral of $ (d^2y/dx^2) dy$ - Mathematics Stack Exchange
Jun 23, 2020 · I saw this as a step in a calculation and it was confusing. The left cancels down to: $$\int \frac {d^2y} {dx^2}dy$$ But surely the answer is $\frac {d^2y} {dx^2}y$; instead, $\frac …